nonzero(self)
Returns a tuple of arrays, one for each dimension, containing the indices of the non-zero elements in that dimension. The corresponding non-zero values can be obtained with:
a[a.nonzero()]
To group the indices by element, rather than dimension, use instead:
np.transpose(a.nonzero())
The result of this is always a 2d array, with a row for each non-zero element.
Indices of elements that are non-zero.
Return the indices of unmasked elements that are not zero.
count_nonzero
Counts the number of non-zero elements in the input array.
flatnonzero
Return indices that are non-zero in the flattened version of the input array.
numpy.ndarray.nonzero
Equivalent ndarray method.
numpy.nonzero
Function operating on ndarrays.
>>> import numpy.ma as maThis example is valid syntax, but we were not able to check execution
... x = ma.array(np.eye(3))
... x masked_array( data=[[1., 0., 0.], [0., 1., 0.], [0., 0., 1.]], mask=False, fill_value=1e+20)
>>> x.nonzero() (array([0, 1, 2]), array([0, 1, 2]))
Masked elements are ignored.
This example is valid syntax, but we were not able to check execution>>> x[1, 1] = ma.maskedThis example is valid syntax, but we were not able to check execution
... x masked_array( data=[[1.0, 0.0, 0.0], [0.0, --, 0.0], [0.0, 0.0, 1.0]], mask=[[False, False, False], [False, True, False], [False, False, False]], fill_value=1e+20)
>>> x.nonzero() (array([0, 2]), array([0, 2]))
Indices can also be grouped by element.
This example is valid syntax, but we were not able to check execution>>> np.transpose(x.nonzero()) array([[0, 0], [2, 2]])
A common use for nonzero
is to find the indices of an array, where a condition is True. Given an array a
, the condition a
> 3 is a boolean array and since False is interpreted as 0, ma.nonzero(a > 3) yields the indices of the a
where the condition is true.
>>> a = ma.array([[1,2,3],[4,5,6],[7,8,9]])This example is valid syntax, but we were not able to check execution
... a > 3 masked_array( data=[[False, False, False], [ True, True, True], [ True, True, True]], mask=False, fill_value=True)
>>> ma.nonzero(a > 3) (array([1, 1, 1, 2, 2, 2]), array([0, 1, 2, 0, 1, 2]))
The nonzero
method of the condition array can also be called.
>>> (a > 3).nonzero() (array([1, 1, 1, 2, 2, 2]), array([0, 1, 2, 0, 1, 2]))See :
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