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fill_diagonal(a, val, wrap=False)

For an array a with a.ndim >= 2 , the diagonal is the list of locations with indices a[i, ..., i] all identical. This function modifies the input array in-place, it does not return a value.

Notes

versionadded

This functionality can be obtained via diag_indices , but internally this version uses a much faster implementation that never constructs the indices and uses simple slicing.

Parameters

a : array, at least 2-D.

Array whose diagonal is to be filled, it gets modified in-place.

val : scalar or array_like

Value(s) to write on the diagonal. If :None:None:`val` is scalar, the value is written along the diagonal. If array-like, the flattened :None:None:`val` is written along the diagonal, repeating if necessary to fill all diagonal entries.

wrap : bool

For tall matrices in NumPy version up to 1.6.2, the diagonal "wrapped" after N columns. You can have this behavior with this option. This affects only tall matrices.

Fill the main diagonal of the given array of any dimensionality.

See Also

diag_indices
diag_indices_from

Examples

>>> a = np.zeros((3, 3), int)
... np.fill_diagonal(a, 5)
... a array([[5, 0, 0], [0, 5, 0], [0, 0, 5]])

The same function can operate on a 4-D array:

>>> a = np.zeros((3, 3, 3, 3), int)
... np.fill_diagonal(a, 4)

We only show a few blocks for clarity:

>>> a[0, 0]
array([[4, 0, 0],
       [0, 0, 0],
       [0, 0, 0]])
>>> a[1, 1]
array([[0, 0, 0],
       [0, 4, 0],
       [0, 0, 0]])
>>> a[2, 2]
array([[0, 0, 0],
       [0, 0, 0],
       [0, 0, 4]])

The wrap option affects only tall matrices:

>>> # tall matrices no wrap
... a = np.zeros((5, 3), int)
... np.fill_diagonal(a, 4)
... a array([[4, 0, 0], [0, 4, 0], [0, 0, 4], [0, 0, 0], [0, 0, 0]])
>>> # tall matrices wrap
... a = np.zeros((5, 3), int)
... np.fill_diagonal(a, 4, wrap=True)
... a array([[4, 0, 0], [0, 4, 0], [0, 0, 4], [0, 0, 0], [4, 0, 0]])
>>> # wide matrices
... a = np.zeros((3, 5), int)
... np.fill_diagonal(a, 4, wrap=True)
... a array([[4, 0, 0, 0, 0], [0, 4, 0, 0, 0], [0, 0, 4, 0, 0]])

The anti-diagonal can be filled by reversing the order of elements using either numpy.flipud or numpy.fliplr .

>>> a = np.zeros((3, 3), int);
... np.fill_diagonal(np.fliplr(a), [1,2,3]) # Horizontal flip
... a array([[0, 0, 1], [0, 2, 0], [3, 0, 0]])
>>> np.fill_diagonal(np.flipud(a), [1,2,3])  # Vertical flip
... a array([[0, 0, 3], [0, 2, 0], [1, 0, 0]])

Note that the order in which the diagonal is filled varies depending on the flip function.

See :

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GitHub : /numpy/lib/index_tricks.py#779
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