vander(x, N=None, increasing=False)
The columns of the output matrix are powers of the input vector. The order of the powers is determined by the :None:None:`increasing`
boolean argument. Specifically, when :None:None:`increasing`
is False, the i
-th output column is the input vector raised element-wise to the power of N - i - 1
. Such a matrix with a geometric progression in each row is named for Alexandre- Theophile Vandermonde.
1-D input array.
Number of columns in the output. If N
is not specified, a square array is returned ( N = len(x)
).
Order of the powers of the columns. If True, the powers increase from left to right, if False (the default) they are reversed.
Vandermonde matrix. If :None:None:`increasing`
is False, the first column is x^(N-1)
, the second x^(N-2)
and so forth. If :None:None:`increasing`
is True, the columns are x^0, x^1, ..., x^(N-1)
.
Generate a Vandermonde matrix.
>>> x = np.array([1, 2, 3, 5])
... N = 3
... np.vander(x, N) array([[ 1, 1, 1], [ 4, 2, 1], [ 9, 3, 1], [25, 5, 1]])
>>> np.column_stack([x**(N-1-i) for i in range(N)]) array([[ 1, 1, 1], [ 4, 2, 1], [ 9, 3, 1], [25, 5, 1]])
>>> x = np.array([1, 2, 3, 5])
... np.vander(x) array([[ 1, 1, 1, 1], [ 8, 4, 2, 1], [ 27, 9, 3, 1], [125, 25, 5, 1]])
>>> np.vander(x, increasing=True) array([[ 1, 1, 1, 1], [ 1, 2, 4, 8], [ 1, 3, 9, 27], [ 1, 5, 25, 125]])
The determinant of a square Vandermonde matrix is the product of the differences between the values of the input vector:
>>> np.linalg.det(np.vander(x)) 48.000000000000043 # may vary
>>> (5-3)*(5-2)*(5-1)*(3-2)*(3-1)*(2-1) 48See :
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