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digitize(x, bins, right=False)

========= ============= ============================ right order of bins returned index i satisfies ========= ============= ============================ False increasing bins[i-1] <= x < bins[i] True increasing bins[i-1] < x <= bins[i] False decreasing bins[i-1] > x >= bins[i] True decreasing bins[i-1] >= x > bins[i] ========= ============= ============================

If values in x are beyond the bounds of :None:None:`bins`, 0 or len(bins) is returned as appropriate.

Notes

If values in x are such that they fall outside the bin range, attempting to index :None:None:`bins` with the indices that digitize returns will result in an IndexError.

versionadded

:None:None:`np.digitize` is implemented in terms of :None:None:`np.searchsorted`. This means that a binary search is used to bin the values, which scales much better for larger number of bins than the previous linear search. It also removes the requirement for the input array to be 1-dimensional.

For monotonically _increasing_ :None:None:`bins`, the following are equivalent:

np.digitize(x, bins, right=True)
np.searchsorted(bins, x, side='left')

Note that as the order of the arguments are reversed, the side must be too. The searchsorted call is marginally faster, as it does not do any monotonicity checks. Perhaps more importantly, it supports all dtypes.

Parameters

x : array_like

Input array to be binned. Prior to NumPy 1.10.0, this array had to be 1-dimensional, but can now have any shape.

bins : array_like

Array of bins. It has to be 1-dimensional and monotonic.

right : bool, optional

Indicating whether the intervals include the right or the left bin edge. Default behavior is (right==False) indicating that the interval does not include the right edge. The left bin end is open in this case, i.e., bins[i-1] <= x < bins[i] is the default behavior for monotonically increasing bins.

Raises

ValueError

If :None:None:`bins` is not monotonic.

TypeError

If the type of the input is complex.

Returns

indices : ndarray of ints

Output array of indices, of same shape as x.

Return the indices of the bins to which each value in input array belongs.

See Also

bincount
histogram
searchsorted
unique

Examples

>>> x = np.array([0.2, 6.4, 3.0, 1.6])
... bins = np.array([0.0, 1.0, 2.5, 4.0, 10.0])
... inds = np.digitize(x, bins)
... inds array([1, 4, 3, 2])
>>> for n in range(x.size):
...  print(bins[inds[n]-1], "<=", x[n], "<", bins[inds[n]]) ... 0.0 <= 0.2 < 1.0 4.0 <= 6.4 < 10.0 2.5 <= 3.0 < 4.0 1.0 <= 1.6 < 2.5
>>> x = np.array([1.2, 10.0, 12.4, 15.5, 20.])
... bins = np.array([0, 5, 10, 15, 20])
... np.digitize(x,bins,right=True) array([1, 2, 3, 4, 4])
>>> np.digitize(x,bins,right=False)
array([1, 3, 3, 4, 5])
See :

Back References

The following pages refer to to this document either explicitly or contain code examples using this.

numpy.bincount numpy.core._multiarray_umath.bincount numpy.digitize skimage.filters.thresholding.threshold_multiotsu numpy.histogram dask.array.routines.digitize

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