choose(indices, choices, out=None, mode='raise')
Given an array of integers and a list of n choice arrays, this method will create a new array that merges each of the choice arrays. Where a value in :None:None:`index` is i, the new array will have the value that choices[i] contains in the same place.
This array must contain integers in [0, n-1]
, where n is the number of choices.
Choice arrays. The index array and all of the choices should be broadcastable to the same shape.
If provided, the result will be inserted into this array. It should be of the appropriate shape and dtype
.
Specifies how out-of-bounds indices will behave.
Use an index array to construct a new array from a list of choices.
choose
equivalent function
>>> choice = np.array([[1,1,1], [2,2,2], [3,3,3]])See :
... a = np.array([2, 1, 0])
... np.ma.choose(a, choice) masked_array(data=[3, 2, 1], mask=False, fill_value=999999)
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