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legsub(c1, c2)

Returns the difference of two Legendre series :None:None:`c1` - :None:None:`c2`. The sequences of coefficients are from lowest order term to highest, i.e., [1,2,3] represents the series P_0 + 2*P_1 + 3*P_2 .

Notes

Unlike multiplication, division, etc., the difference of two Legendre series is a Legendre series (without having to "reproject" the result onto the basis set) so subtraction, just like that of "standard" polynomials, is simply "component-wise."

Parameters

c1, c2 : array_like: 1-D arrays of Legendre series coefficients ordered from low to high.

Returns

out : ndarray: Of Legendre series coefficients representing their difference.

Subtract one Legendre series from another.

Examples

>>> from numpy.polynomial import legendre as L
... c1 = (1,2,3)
... c2 = (3,2,1)
... L.legsub(c1,c2)
array([-2.,  0.,  2.])

>>> L.legsub(c2,c1) # -C.legsub(c1,c2)
array([ 2.,  0., -2.])

See :

Back References

The following pages refer to to this document either explicitly or contain code examples using this.

numpy.polynomial.legendre.legpow numpy.polynomial.legendre.legmul numpy.polynomial.legendre.legdiv numpy.polynomial.legendre.legadd

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