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legder(c, m=1, scl=1, axis=0)

Returns the Legendre series coefficients c differentiated m times along :None:None:`axis`. At each iteration the result is multiplied by :None:None:`scl` (the scaling factor is for use in a linear change of variable). The argument c is an array of coefficients from low to high degree along each axis, e.g., [1,2,3] represents the series 1*L_0 + 2*L_1 + 3*L_2 while [[1,2],[1,2]] represents 1*L_0(x)*L_0(y) + 1*L_1(x)*L_0(y) + 2*L_0(x)*L_1(y) + 2*L_1(x)*L_1(y) if axis=0 is x and axis=1 is y .

Notes

In general, the result of differentiating a Legendre series does not resemble the same operation on a power series. Thus the result of this function may be "unintuitive," albeit correct; see Examples section below.

Parameters

c : array_like

Array of Legendre series coefficients. If c is multidimensional the different axis correspond to different variables with the degree in each axis given by the corresponding index.

m : int, optional

Number of derivatives taken, must be non-negative. (Default: 1)

scl : scalar, optional

Each differentiation is multiplied by :None:None:`scl`. The end result is multiplication by scl**m . This is for use in a linear change of variable. (Default: 1)

axis : int, optional

Axis over which the derivative is taken. (Default: 0).

versionadded

Returns

der : ndarray

Legendre series of the derivative.

Differentiate a Legendre series.

See Also

legint

Examples

>>> from numpy.polynomial import legendre as L
... c = (1,2,3,4)
... L.legder(c) array([ 6., 9., 20.])
>>> L.legder(c, 3)
array([60.])
>>> L.legder(c, scl=-1)
array([ -6.,  -9., -20.])
>>> L.legder(c, 2,-1)
array([  9.,  60.])
See :

Back References

The following pages refer to to this document either explicitly or contain code examples using this.

numpy.polynomial.legendre.legint

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GitHub : /numpy/polynomial/legendre.py#612
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