step2(system, X0=None, T=None, N=None, **kwargs)
This function is functionally the same as scipy.signal.step
, but it uses the function scipy.signal.lsim2
to compute the step response.
If (num, den) is passed in for system
, coefficients for both the numerator and denominator should be specified in descending exponent order (e.g. s^2 + 3s + 5
would be represented as [1, 3, 5]
).
describing the system. The following gives the number of elements in the tuple and the interpretation:
1 (instance of
lti)2 (num, den)
3 (zeros, poles, gain)
4 (A, B, C, D)
Initial state-vector (default is zero).
Time points (computed if not given).
Number of time points to compute if T is not given.
Additional keyword arguments are passed on the function scipy.signal.lsim2
, which in turn passes them on to scipy.integrate.odeint
. See the documentation for scipy.integrate.odeint
for information about these arguments.
Step response of continuous-time system.
>>> from scipy import signalSee :
... import matplotlib.pyplot as plt
... lti = signal.lti([1.0], [1.0, 1.0])
... t, y = signal.step2(lti)
... plt.plot(t, y)
... plt.xlabel('Time [s]')
... plt.ylabel('Amplitude')
... plt.title('Step response for 1. Order Lowpass')
... plt.grid()
The following pages refer to to this document either explicitly or contain code examples using this.
scipy.signal._ltisys.step
scipy.signal._ltisys.step2
scipy.signal._ltisys._default_response_times
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