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impulse2(system, X0=None, T=None, N=None, **kwargs)

Notes

The solution is generated by calling scipy.signal.lsim2 , which uses the differential equation solver scipy.integrate.odeint .

If (num, den) is passed in for system , coefficients for both the numerator and denominator should be specified in descending exponent order (e.g. s^2 + 3s + 5 would be represented as [1, 3, 5] ).

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Parameters

system : an instance of the LTI class or a tuple of array_like

describing the system. The following gives the number of elements in the tuple and the interpretation:

1 (instance of lti )

2 (num, den)

3 (zeros, poles, gain)

4 (A, B, C, D)

X0 : 1-D array_like, optional

The initial condition of the state vector. Default: 0 (the zero vector).

T : 1-D array_like, optional

The time steps at which the input is defined and at which the output is desired. If T is not given, the function will generate a set of time samples automatically.

N : int, optional

Number of time points to compute. Default: 100.

kwargs : various types

Additional keyword arguments are passed on to the function scipy.signal.lsim2 , which in turn passes them on to scipy.integrate.odeint ; see the latter's documentation for information about these arguments.

Returns

T : ndarray: The time values for the output.
yout : ndarray: The output response of the system.

Impulse response of a single-input, continuous-time linear system.

Examples

Compute the impulse response of a second order system with a repeated root: x''(t) + 2*x'(t) + x(t) = u(t)

>>> from scipy import signal
... system = ([1.0], [1.0, 2.0, 1.0])
... t, y = signal.impulse2(system)
... import matplotlib.pyplot as plt
... plt.plot(t, y)

See :

Back References

The following pages refer to to this document either explicitly or contain code examples using this.

scipy.signal._ltisys._default_response_times scipy.signal._ltisys.impulse2

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