splder(tck, n=1)
Spline whose derivative to compute
Order of derivative to evaluate. Default: 1
Spline of order k2=k-n representing the derivative of the input spline.
Compute the spline representation of the derivative of a given spline
This can be used for finding maxima of a curve:
>>> from scipy.interpolate import splrep, splder, sproot
... x = np.linspace(0, 10, 70)
... y = np.sin(x)
... spl = splrep(x, y, k=4)
Now, differentiate the spline and find the zeros of the derivative. (NB: sproot
only works for order 3 splines, so we fit an order 4 spline):
>>> dspl = splder(spl)
... sproot(dspl) / np.pi array([ 0.50000001, 1.5 , 2.49999998])
This agrees well with roots $\pi/2 + n\pi$ of $\cos(x) = \sin'(x)$ .
See :The following pages refer to to this document either explicitly or contain code examples using this.
scipy.interpolate._fitpack_impl.splantider
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