hfft
/ihfft
are a pair analogous to rfft
/irfft
, but for the opposite case: here the signal has Hermitian symmetry in the time domain and is real in the frequency domain. So, here, it's hfft
, for which you must supply the length of the result if it is to be odd. * even: ihfft(hfft(a, 2*len(a) - 2) == a
, within roundoff error, * odd: ihfft(hfft(a, 2*len(a) - 1) == a
, within roundoff error.
The input array.
Length of the transformed axis of the output. For n
output points, n//2 + 1
input points are necessary. If the input is longer than this, it is cropped. If it is shorter than this, it is padded with zeros. If n
is not given, it is taken to be 2*(m-1)
, where m
is the length of the input along the axis specified by :None:None:`axis`
.
Axis over which to compute the FFT. If not given, the last axis is used.
Normalization mode (see fft
). Default is "backward".
If True, the contents of x
can be destroyed; the default is False. See fft
for more details.
Maximum number of workers to use for parallel computation. If negative, the value wraps around from os.cpu_count()
. See ~scipy.fft.fft
for more details.
This argument is reserved for passing in a precomputed plan provided by downstream FFT vendors. It is currently not used in SciPy.
If :None:None:`axis`
is larger than the last axis of a
.
The truncated or zero-padded input, transformed along the axis indicated by :None:None:`axis`
, or the last one if :None:None:`axis`
is not specified. The length of the transformed axis is n
, or, if n
is not given, 2*m - 2
, where m
is the length of the transformed axis of the input. To get an odd number of output points, n
must be specified, for instance, as 2*m - 1
in the typical case,
Compute the FFT of a signal that has Hermitian symmetry, i.e., a real spectrum.
hfftn
Compute the N-D FFT of a Hermitian signal.
ihfft
The inverse of :None:None:`hfft`
.
rfft
Compute the 1-D FFT for real input.
>>> from scipy.fft import fft, hfft
... a = 2 * np.pi * np.arange(10) / 10
... signal = np.cos(a) + 3j * np.sin(3 * a)
... fft(signal).round(10) array([ -0.+0.j, 5.+0.j, -0.+0.j, 15.-0.j, 0.+0.j, 0.+0.j, -0.+0.j, -15.-0.j, 0.+0.j, 5.+0.j])
>>> hfft(signal[:6]).round(10) # Input first half of signal array([ 0., 5., 0., 15., -0., 0., 0., -15., -0., 5.])
>>> hfft(signal, 10) # Input entire signal and truncate array([ 0., 5., 0., 15., -0., 0., 0., -15., -0., 5.])See :
The following pages refer to to this document either explicitly or contain code examples using this.
scipy.fft._basic.ihfftn
scipy.fft._basic.hfft
scipy.fft._helper.next_fast_len
scipy.fft._basic.ihfft
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