bisect(f, a, b, args=(), xtol=2e-12, rtol=8.881784197001252e-16, maxiter=100, full_output=False, disp=True)
Basic bisection routine to find a zero of the function f
between the arguments a
and b
. :None:None:`f(a)`
and :None:None:`f(b)`
cannot have the same signs. Slow but sure.
Python function returning a number. f
must be continuous, and f(a) and f(b) must have opposite signs.
One end of the bracketing interval [a,b].
The other end of the bracketing interval [a,b].
The computed root x0
will satisfy np.allclose(x, x0,
atol=xtol, rtol=rtol)
, where x
is the exact root. The parameter must be nonnegative.
The computed root x0
will satisfy np.allclose(x, x0,
atol=xtol, rtol=rtol)
, where x
is the exact root. The parameter cannot be smaller than its default value of 4*np.finfo(float).eps
.
If convergence is not achieved in :None:None:`maxiter`
iterations, an error is raised. Must be >= 0.
Containing extra arguments for the function f
. f
is called by apply(f, (x)+args)
.
If :None:None:`full_output`
is False, the root is returned. If :None:None:`full_output`
is True, the return value is (x, r)
, where x is the root, and r is a RootResults
object.
If True, raise RuntimeError if the algorithm didn't converge. Otherwise, the convergence status is recorded in a RootResults
return object.
Object containing information about the convergence. In particular, r.converged
is True if the routine converged.
Find root of a function within an interval using bisection.
fixed_point
scalar fixed-point finder
fsolve
n-dimensional root-finding
>>> def f(x):
... return (x**2 - 1)
>>> from scipy import optimize
>>> root = optimize.bisect(f, 0, 2)
... root 1.0
>>> root = optimize.bisect(f, -2, 0)See :
... root -1.0
The following pages refer to to this document either explicitly or contain code examples using this.
scipy.optimize._zeros_py.bisect
scipy.optimize._zeros_py.toms748
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