pandas 1.4.2

Returns
_sort_levels_monotonic(self) -> 'MultiIndex'

Create a new MultiIndex from the current to monotonically sorted items IN the levels. This does not actually make the entire MultiIndex monotonic, JUST the levels.

The resulting MultiIndex will have the same outward appearance, meaning the same .values and ordering. It will also be .equals() to the original.

Returns

MultiIndex

This is an internal function.

Examples

This example is valid syntax, but we were not able to check execution
>>> mi = pd.MultiIndex(levels=[['a', 'b'], ['bb', 'aa']],
...  codes=[[0, 0, 1, 1], [0, 1, 0, 1]])
... mi MultiIndex([('a', 'bb'), ('a', 'aa'), ('b', 'bb'), ('b', 'aa')], )
This example is valid syntax, but we were not able to check execution
>>> mi.sort_values()
MultiIndex([('a', 'aa'),
            ('a', 'bb'),
            ('b', 'aa'),
            ('b', 'bb')],
           )
See :

Local connectivity graph

Hover to see nodes names; edges to Self not shown, Caped at 50 nodes.

Using a canvas is more power efficient and can get hundred of nodes ; but does not allow hyperlinks; , arrows or text (beyond on hover)

SVG is more flexible but power hungry; and does not scale well to 50 + nodes.

All aboves nodes referred to, (or are referred from) current nodes; Edges from Self to other have been omitted (or all nodes would be connected to the central node "self" which is not useful). Nodes are colored by the library they belong to, and scaled with the number of references pointing them


File: /pandas/core/indexes/multi.py#1900
type: <class 'function'>
Commit: