pandas 1.4.2

NotesParametersReturnsBackRef
join(self, other: 'DataFrame | Series', on: 'IndexLabel | None' = None, how: 'str' = 'left', lsuffix: 'str' = '', rsuffix: 'str' = '', sort: 'bool' = False) -> 'DataFrame'

Join columns with other DataFrame either on index or on a key column. Efficiently join multiple DataFrame objects by index at once by passing a list.

Notes

Parameters :None:None:`on`, :None:None:`lsuffix`, and :None:None:`rsuffix` are not supported when passing a list of DataFrame objects.

Support for specifying index levels as the :None:None:`on` parameter was added in version 0.23.0.

Parameters

other : DataFrame, Series, or list of DataFrame

Index should be similar to one of the columns in this one. If a Series is passed, its name attribute must be set, and that will be used as the column name in the resulting joined DataFrame.

on : str, list of str, or array-like, optional

Column or index level name(s) in the caller to join on the index in other , otherwise joins index-on-index. If multiple values given, the other DataFrame must have a MultiIndex. Can pass an array as the join key if it is not already contained in the calling DataFrame. Like an Excel VLOOKUP operation.

how : {'left', 'right', 'outer', 'inner'}, default 'left'

How to handle the operation of the two objects.

  • left: use calling frame's index (or column if on is specified)

  • right: use other 's index.

  • outer: form union of calling frame's index (or column if on is specified) with other 's index, and sort it. lexicographically.

  • inner: form intersection of calling frame's index (or column if on is specified) with other 's index, preserving the order of the calling's one.

  • cross: creates the cartesian product from both frames, preserves the order of the left keys.

    versionadded
lsuffix : str, default ''

Suffix to use from left frame's overlapping columns.

rsuffix : str, default ''

Suffix to use from right frame's overlapping columns.

sort : bool, default False

Order result DataFrame lexicographically by the join key. If False, the order of the join key depends on the join type (how keyword).

Returns

DataFrame

A dataframe containing columns from both the caller and other .

Join columns of another DataFrame.

See Also

DataFrame.merge

For column(s)-on-column(s) operations.

Examples

This example is valid syntax, but we were not able to check execution
>>> df = pd.DataFrame({'key': ['K0', 'K1', 'K2', 'K3', 'K4', 'K5'],
...  'A': ['A0', 'A1', 'A2', 'A3', 'A4', 'A5']})
This example is valid syntax, but we were not able to check execution
>>> df
  key   A
0  K0  A0
1  K1  A1
2  K2  A2
3  K3  A3
4  K4  A4
5  K5  A5
This example is valid syntax, but we were not able to check execution
>>> other = pd.DataFrame({'key': ['K0', 'K1', 'K2'],
...  'B': ['B0', 'B1', 'B2']})
This example is valid syntax, but we were not able to check execution
>>> other
  key   B
0  K0  B0
1  K1  B1
2  K2  B2

Join DataFrames using their indexes.

This example is valid syntax, but we were not able to check execution
>>> df.join(other, lsuffix='_caller', rsuffix='_other')
  key_caller   A key_other    B
0         K0  A0        K0   B0
1         K1  A1        K1   B1
2         K2  A2        K2   B2
3         K3  A3       NaN  NaN
4         K4  A4       NaN  NaN
5         K5  A5       NaN  NaN

If we want to join using the key columns, we need to set key to be the index in both :None:None:`df` and other . The joined DataFrame will have key as its index.

This example is valid syntax, but we were not able to check execution
>>> df.set_index('key').join(other.set_index('key'))
      A    B
key
K0   A0   B0
K1   A1   B1
K2   A2   B2
K3   A3  NaN
K4   A4  NaN
K5   A5  NaN

Another option to join using the key columns is to use the :None:None:`on` parameter. DataFrame.join always uses other 's index but we can use any column in :None:None:`df`. This method preserves the original DataFrame's index in the result.

This example is valid syntax, but we were not able to check execution
>>> df.join(other.set_index('key'), on='key')
  key   A    B
0  K0  A0   B0
1  K1  A1   B1
2  K2  A2   B2
3  K3  A3  NaN
4  K4  A4  NaN
5  K5  A5  NaN

Using non-unique key values shows how they are matched.

This example is valid syntax, but we were not able to check execution
>>> df = pd.DataFrame({'key': ['K0', 'K1', 'K1', 'K3', 'K0', 'K1'],
...  'A': ['A0', 'A1', 'A2', 'A3', 'A4', 'A5']})
This example is valid syntax, but we were not able to check execution
>>> df
  key   A
0  K0  A0
1  K1  A1
2  K1  A2
3  K3  A3
4  K0  A4
5  K1  A5
This example is valid syntax, but we were not able to check execution
>>> df.join(other.set_index('key'), on='key')
  key   A    B
0  K0  A0   B0
1  K1  A1   B1
2  K1  A2   B1
3  K3  A3  NaN
4  K0  A4   B0
5  K1  A5   B1
See :

Back References

The following pages refer to to this document either explicitly or contain code examples using this.

pandas.core.reshape.merge.merge pandas.core.reshape.concat.concat pandas.core.frame.DataFrame.merge

Local connectivity graph

Hover to see nodes names; edges to Self not shown, Caped at 50 nodes.

Using a canvas is more power efficient and can get hundred of nodes ; but does not allow hyperlinks; , arrows or text (beyond on hover)

SVG is more flexible but power hungry; and does not scale well to 50 + nodes.

All aboves nodes referred to, (or are referred from) current nodes; Edges from Self to other have been omitted (or all nodes would be connected to the central node "self" which is not useful). Nodes are colored by the library they belong to, and scaled with the number of references pointing them


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