append(self, other, ignore_index: 'bool' = False, verify_integrity: 'bool' = False, sort: 'bool' = False) -> 'DataFrame'
Use :None:func:`concat`
instead. For further details see :None:ref:`whatsnew_140.deprecations.frame_series_append`
Columns in other
that are not in the caller are added as new columns.
If a list of dict/series is passed and the keys are all contained in the DataFrame's index, the order of the columns in the resulting DataFrame will be unchanged.
Iteratively appending rows to a DataFrame can be more computationally intensive than a single concatenate. A better solution is to append those rows to a list and then concatenate the list with the original DataFrame all at once.
The data to append.
If True, the resulting axis will be labeled 0, 1, …, n - 1.
If True, raise ValueError on creating index with duplicates.
Sort columns if the columns of :None:None:`self`
and other
are not aligned.
Changed to not sort by default.
A new DataFrame consisting of the rows of caller and the rows of other
.
Append rows of other
to the end of caller, returning a new object.
concat
General function to concatenate DataFrame or Series objects.
>>> df = pd.DataFrame([[1, 2], [3, 4]], columns=list('AB'), index=['x', 'y'])This example is valid syntax, but we were not able to check execution
... df A B x 1 2 y 3 4
>>> df2 = pd.DataFrame([[5, 6], [7, 8]], columns=list('AB'), index=['x', 'y'])
... df.append(df2) A B x 1 2 y 3 4 x 5 6 y 7 8
With :None:None:`ignore_index`
set to True:
>>> df.append(df2, ignore_index=True) A B 0 1 2 1 3 4 2 5 6 3 7 8
The following, while not recommended methods for generating DataFrames, show two ways to generate a DataFrame from multiple data sources.
Less efficient:
This example is valid syntax, but we were not able to check execution>>> df = pd.DataFrame(columns=['A'])
... for i in range(5):
... df = df.append({'A': i}, ignore_index=True)
... df A 0 0 1 1 2 2 3 3 4 4
More efficient:
This example is valid syntax, but we were not able to check execution>>> pd.concat([pd.DataFrame([i], columns=['A']) for i in range(5)],See :
... ignore_index=True) A 0 0 1 1 2 2 3 3 4 4
The following pages refer to to this document either explicitly or contain code examples using this.
pandas.core.reshape.concat.concat
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