diff(self, periods: 'int' = 1) -> 'Series'
Calculates the difference of a Series element compared with another element in the Series (default is element in previous row).
For boolean dtypes, this uses operator.xor
rather than operator.sub
. The result is calculated according to current dtype in Series, however dtype of the result is always float64.
Periods to shift for calculating difference, accepts negative values.
First differences of the Series.
First discrete difference of element.
DataFrame.diff
First discrete difference of object.
Series.pct_change
Percent change over given number of periods.
Series.shift
Shift index by desired number of periods with an optional time freq.
Difference with previous row
This example is valid syntax, but we were not able to check execution>>> s = pd.Series([1, 1, 2, 3, 5, 8])
... s.diff() 0 NaN 1 0.0 2 1.0 3 1.0 4 2.0 5 3.0 dtype: float64
Difference with 3rd previous row
This example is valid syntax, but we were not able to check execution>>> s.diff(periods=3) 0 NaN 1 NaN 2 NaN 3 2.0 4 4.0 5 6.0 dtype: float64
Difference with following row
This example is valid syntax, but we were not able to check execution>>> s.diff(periods=-1) 0 0.0 1 -1.0 2 -1.0 3 -2.0 4 -3.0 5 NaN dtype: float64
Overflow in input dtype
This example is valid syntax, but we were not able to check execution>>> s = pd.Series([1, 0], dtype=np.uint8)See :
... s.diff() 0 NaN 1 255.0 dtype: float64
The following pages refer to to this document either explicitly or contain code examples using this.
pandas.core.frame.DataFrame.diff
pandas.core.generic.NDFrame.pct_change
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