searchsorted(self, value: 'NumpyValueArrayLike | ExtensionArray', side: "Literal['left', 'right']" = 'left', sorter: 'NumpySorter' = None) -> 'npt.NDArray[np.intp] | np.intp'
Find the indices into a sorted array :None:None:`self` (a) such that, if the corresponding elements in :None:None:`value` were inserted before the indices, the order of :None:None:`self` would be preserved.
Assuming that :None:None:`self` is sorted:
====== ================================ :None:None:`side` returned index i satisfies ====== ================================ left self[i-1] < value <= self[i]
right self[i-1] <= value < self[i]
====== ================================
Value(s) to insert into :None:None:`self`.
If 'left', the index of the first suitable location found is given. If 'right', return the last such index. If there is no suitable index, return either 0 or N (where N is the length of :None:None:`self`).
Optional array of integer indices that sort array a into ascending order. They are typically the result of argsort.
If value is array-like, array of insertion points. If value is scalar, a single integer.
Find indices where elements should be inserted to maintain order.
numpy.searchsorted
Similar method from NumPy.
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